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Experiment #4






 

We remove the experimental dependence of the resistance between two rod electrodes on the distance D between them. The bars were immersed in water at 0.15 m. The results of this experiment are listed in the table #3.

 

 

Table #3
z, cm r, Ohm D a12 a11 C r
    0, 05 9, 86E+10 2, 23E+11 4, 04E-12 294, 36
    0, 1 6, 58E+10 2, 23E+11 3, 19E-12 372, 30
    0, 15 4, 95E+10 2, 23E+11 2, 89E-12 411, 07
    0, 2 3, 96E+10 2, 23E+11 2, 73E-12 434, 72
    0, 25 3, 28E+10 2, 23E+11 2, 64E-12 450, 68
    0, 35 2, 44E+10 2, 23E+11 2, 52E-12 470, 75

 

The resulting relationship is shown in the schedule #3.

For the experiment using two rods a theoretical dependence of the resistance on the distance between the rods, designed with the help of potential factors. According to this method it is possible to draw an analogy between the relations that characterize the stationary electric field of direct currents in the conductive medium and the relations that characterize the electrostatic field in the dielectric. The ratio of the electric conductivity G to C body capacity equal to the ratio of the specific conductivity of the medium gamma, ambient electrode to the dielectric constant ε:

Capacity rods arranged in a uniform dielectric with dielectric constant ε and the capacitance between the two rods can be expressed in terms of their own and mutual potential coefficients. Moreover, since the rods are identical, their own mutual ratios equal.

 

 

Sample calculation for line 2:

Own a potential factor of each rod:

Where, – it is the distance between the two rods in meters

– the radius of rod in the meters

– the length of the bar, designed in a special way:

because of the method of electrostatic analogy, we need to have a uniform medium that did not comply with the conditions of our experiment, in which a portion of the rods was under water, and is often found in the air. However, one can use the method with respect to the mirror image of that part of the rod which was in the water. The bars were immersed in water at 0.15 m, then l - 0.3 meters, and the resulting capacity twice to determine the necessary resistance, which should be considered in the calculations.

Mutual potential factor:

The capacity of the two bars:


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